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[python] accumulate(itertools), λˆ„μ  ν•©
Programming language/Python

[python] accumulate(itertools), λˆ„μ  ν•©

2020. 8. 30. 20:19
λ°˜μ‘ν˜•

πŸ“— accumulate

λœ»μœΌλ‘œλŠ” μΆ•μ ν•˜λ‹€?

ν•œλ§ˆλ””λ‘œ λˆ„μ λœ 합을 λ½‘μ•„μ£ΌλŠ” 녀석

πŸ”΅ μ‚¬μš©λ²•

from itertools import accumulate

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = list(accumulate(a))
print(a)  # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(b)  # [1, 3, 6, 10, 15, 21, 28, 36, 45, 55]

값이 μ €μ ˆλ‘œ λˆ„μ λ˜λŠ” 것을 λ³Ό 수 μžˆλ‹€.

이것을 μ™œ μ‚¬μš©ν•˜λŠλƒν•˜λ©΄

사싀 forλ¬Έ λ§ŒμœΌλ‘œλ„ 값을 λˆ„μ ν•œ 리슀트λ₯Ό 뽑을 수 μžˆμ§€λ§Œ μ†λ„λ©΄μ—μ„œ 큰 차이가 λ‚œλ‹€.( 특히 값이 컀지면 컀질수둝 )

 

πŸ”΅ 속도 μΈ‘μ •

1번 for문

a = [x+1 for x in range(1000000)]
for i in range(1, len(a)):
    a[i] += a[i-1]

2번 accumulate

a = [x+1 for x in range(1000000)]
b = list(accumulate(a))
μ‹€ν–‰ μ½”λ“œ κ°’ 속도
for문 10만 0.01894974708557129
accumulate 10만 0.004986286163330078
for문 1000만 1.868004560470581
accumulate 1000만 0.766948938369751

accumulateκ°€ ν™•μ‹€νžˆ λΉ λ₯Έκ²ƒμ„ λ³Ό 수 μžˆλ‹€. 많이 μ‚¬μš©ν•  일은 μ—†κ² μ§€λ§Œ μ•Œμ•„λ‘λ©΄ 쒋을 것 κ°™λ‹€.

λ°˜μ‘ν˜•
μ €μž‘μžν‘œμ‹œ λΉ„μ˜λ¦¬ λ³€κ²½κΈˆμ§€ (μƒˆμ°½μ—΄λ¦Ό)

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    'Programming language/Python' μΉ΄ν…Œκ³ λ¦¬μ˜ λ‹€λ₯Έ κΈ€
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